7.6 / 10 123... May 2026

7.6 / 10 123... May 2026

: This method returns the starting index of the first occurrence of letter . If it isn't found, it returns -1 .

: If letter is an empty string, the loop would run forever; we return the original word immediately.

You can solve this using a while loop to repeatedly find and remove the target substring until it no longer exists in the word. 7.6 / 10 123...

: The while True ensures the code keeps searching until every instance is gone, which is necessary if the letter appears multiple times (e.g., removing "na" from "banana"). Alternative (Standard Python)

def remove_all_from_string(word, letter): return word.replace(letter, "") Use code with caution. Copied to clipboard : This method returns the starting index of

: word[:index] takes everything before the letter, and word[index + len(letter):] takes everything after it. Adding them together effectively "deletes" the unwanted part.

The prompt likely refers to from the CodeHS Python curriculum. This exercise requires you to write a function that removes every instance of a specific "letter" (or substring) from a given word. Correct Python Implementation You can solve this using a while loop

While the CodeHS exercise often requires the manual loop approach above, the simplest way to do this in standard Python is using the .replace() method: