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5 Klass Matematika Didakticheskii Material Stranitsa 52 V 1 Ershova -

: The numerator must be greater than or equal to the denominator ( Possible values:

: Usually involving the total distance or amount after several parts are consumed or traveled. Step-by-Step Analysis of Key Problems 1. Calculate a Part from a Whole Problem : In a school, there are 48 fifth-graders. 38three-eighths of them are girls. How many girls are in the fifth grade? Divide the total by the denominator : To find one part ( 18one-eighth ), divide the total number of students by 8. 48÷8=648 divided by 8 equals 6 : The numerator must be greater than or

: Understanding that the bottom number indicates how many equal parts the whole is divided into. 38three-eighths of them are girls

: Determining which fractions are proper (less than 1) or improper (greater than or equal to 1). Solving simple fraction equations : Finding in expressions like 48÷8=648 divided by 8 equals 6 : Understanding

: Find the numbers that satisfy both conditions. The numbers work for both. 3. Solving Fraction Equations Example : Solve

Контрольные работы. 5 класс. С образцами решения.